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Equilibrium States

 

The first step in analyzing any nonlinear system is the identification of its equilibrium states. The equilibrium states are the stationary points of the system, that is, where the system comes to rest. For a system of differential equations, the equilibrium states are calculated by setting all the time derivatives equal to zero in the unforced system . Setting tex2html_wrap_inline13621 , tex2html_wrap_inline13623 , and A = 0 in equation (3.14), we immediately find that the location of the equilibrium solutions is given by

  equation2857

which, in general, has three solutions:

  equation2860

Clearly, there is only one real solution if K ;SPMgt; 0, tex2html_wrap_inline11259 , since the other two solutions, tex2html_wrap_inline13631 , are imaginary in this case. If K ;SPMlt; 0, then there are three real solutions.

To understand the stability of the stationary points it is useful to recall the physical model that goes with equation (3.14). If tex2html_wrap_inline13635 , then K ;SPMlt; 0 (see eqs. (3.4 and 3.5)) and the Duffing equation (3.14) is a simple model for a beam  under a compressive load. As illustrated in Figure 3.4, the solutions tex2html_wrap_inline13631 correspond to the two asymmetric stable beam configurations.

  
Figure 3.4: Equilibrium states of a beam under a compressive load.

The position tex2html_wrap_inline11259 corresponds to the symmetric unstable beam configuration--a small tap on the beam would immediately send it to one of the tex2html_wrap_inline13631 configurations. If tex2html_wrap_inline13645 , then K ;SPMgt; 0 and the Duffing equation is a simple model of a string or wire under tension, so there is only one symmetric stable configuration, tex2html_wrap_inline11259 (Fig. 3.5).

  
Figure 3.5: Equilibrium state of a wire under tension.



Nicholas B. Tufillaro
Mon Mar 3 01:58:02 PST 1997