Solving equation (2.10) for x we find two period one
solutions,
and
The first period one orbit, labeled 
,
always remains at the origin, while the location of the second period one orbit,
, depends on 
. From equation (2.12), the stability of each of
these orbits is determined from
and
Clearly, if 
then 
and 
, so
the period one orbit is stable and is unstable. At 
these two orbits collide and exchange stability so that for 
, is unstable and is stable. For 
, both orbits are unstable.
