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Stationary Table

 

First, though, we must figure out how the ball's velocity changes at each impact. Consider two different reference frames: the ball's motion as seen from the ground (the ground's reference frame) and the ball's motion as seen from the table (the table's reference frame). Begin by considering the simple case where the table is stationary and the two reference frames are identical. As we will show shortly, understanding the stationary case will solve the nonstationary case.

Let tex2html_wrap_inline11540 be the ball's velocity right before the kth impact, and let tex2html_wrap_inline11544 be the ball's velocity right after the kth impact. The prime notation indicates a velocity immediately before an impact. If the table is stationary and the collisions are elastic, then tex2html_wrap_inline11548 : the ball reverses direction but does not change speed since there is no energy loss. If the collisions are inelastic and the table is stationary, then the ball's speed will be reduced after the collision because energy is lost: tex2html_wrap_inline11550 , where tex2html_wrap_inline11245 is the coefficient of restitution . The constant tex2html_wrap_inline11245 is a measure of the energy loss at each impact. If tex2html_wrap_inline11556 , the system is conservative and the collisions are elastic. The coefficient of restitution is strictly less than one for inelastic collisions.gif



Nicholas B. Tufillaro
Mon Mar 3 01:58:02 PST 1997